20x^2+110x-210=0

Solution for 20x^2+110x-210=0 equation:

20x^2+110x-210=0

a = 20; b = 110; c = -210;
Δ = b2-4ac
Δ = 1102-4·20·(-210)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28900}=170$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-170}{2*20}=\frac{-280}{40}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+170}{2*20}=\frac{60}{40}
=1+1/2
$